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(B, D) $1$. Hydration of propene $(CH_3-CH=CH_2)$ with dilute $H_2SO_4$ follows Markovnikov's rule to give propan$-2-$ol (secondary alcohol).$2$. Hydr

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Catalytic reduction of butanal

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(B, D) $1$. Hydration of propene $(CH_3-CH=CH_2)$ with dilute $H_2SO_4$ follows Markovnikov's rule to give propan$-2-$ol (secondary alcohol).$2$. Hydroboration-oxidation of propene $(CH_3-CH=CH_2)$ with $BH_3$ followed by $H_2O_2/OH^-$ follows anti-Markovnikov's rule to give propan$-1-$ol (primary alcohol).$3$. Reaction of propanone $(CH_3COCH_3)$ with $CH_3MgBr$ followed by hydrolysis gives $2-$methylpropan$-2-$ol (tertiary alcohol).$4$. Catalytic reduction of butanal $(CH_3CH_2CH_2CHO)$ with $H_2/Ni$ gives butan$-1-$ol (primary alcohol).Both options $B$ and $D$ produce primary alcohols. However,in standard multiple-choice contexts where only one is expected,both are chemically valid. Given the phrasing,both are correct.

Column-$I$	Column-$II$
$A$. Methanol	$p$. Conversion of phenol to salicylic acid
$B$. Kolbe's reaction	$q$. Wood spirit
$C$. Williamson's reaction	$r$. Vapours are passed over heated copper at $573 \ K$
$D$. Conversion of $2^\circ$ alcohol to ketone	$s$. Reaction of alkyl halide with sodium alkoxide

Column-$I$: Compound / Reagent	Column-$II$: Other name / Chemical / Process
$A$. Methanol	$I$. Lucas reagent
$B$. $ZnCl_2$ / Conc. $HCl$	$II$. Baeyer's reagent
$C$. Rectified spirit	$III$. Wood spirit
$D$. Dil. $KMnO_4$	$IV$. $95 \% C_2H_5OH$
-	$V$. $75 \% C_2H_5OH$
-	$VI$. $90 \% C_3H_7OH$

Which of the following reactions will produce a primary alcohol?

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